144x^2-435=0

Solution for 144x^2-435=0 equation:

144x^2-435=0

a = 144; b = 0; c = -435;
Δ = b2-4ac
Δ = 02-4·144·(-435)
Δ = 250560
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{250560}=\sqrt{576*435}=\sqrt{576}*\sqrt{435}=24\sqrt{435}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{435}}{2*144}=\frac{0-24\sqrt{435}}{288}
=-\frac{24\sqrt{435}}{288}
=-\frac{\sqrt{435}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{435}}{2*144}=\frac{0+24\sqrt{435}}{288}
=\frac{24\sqrt{435}}{288}
=\frac{\sqrt{435}}{12}
$